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Theory · Physics Circle Master Book

Electromagnetic Waves

01
CONCEPT

Nature of EM Waves & Their Direction

In one line
A changing electric field makes a changing magnetic field, and a changing magnetic field makes a changing electric field. Together they travel as a transverse wave.
NATURE

32.1.1 What is an EM wave?

  1. E and B oscillate with time and keep creating each other.
  2. They need no material medium; they travel through vacuum at speed c.
  3. They are transverse; polarization proves this.
  4. They carry energy and momentum.
  5. They carry no charge, so E and B fields do not deflect them.
  6. The electric vector causes the optical effects, so it is called the light vector.
c (x)E (y)B (z)λ
E and B oscillate in phase, at right angles to each other and to c
PHASE

32.1.2 E and B together

  1. E and B are always in phase: both reach maximum and zero together.
  2. E ⊥ B, and both are ⊥ to the direction of travel.
DIRECTION

32.1.3 Direction of propagation

direction of travel = E × B
EBcE × B along c
E, B and c form a right-handed set
E alongB alongWave travels along
+x+y+z
+y+z+x
+z+x+y
  1. Use î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ.
  2. Reversing the order gives a minus sign.
  3. Unit vector along travel: k̂ = Ê × B̂.
FINDING B

32.1.4 B from k and E

B = k × Eω
  1. k is the propagation vector, along the direction of travel.
  2. A wave along y can have only x and z components of E and B.
  3. For valid E and B directions: E · B = 0, and E × B is along the travel.
Practise PYQs on this topicNature of EM Waves & Wave Equation · 93 questions with solutions
02
CONCEPT

Wave Equation, E0 = cB0 & Force on a Charge

In one line
The two fields follow the same sine wave. The ratio of their amplitudes is always the wave speed: E0 = cB0.
WAVE EQUATION

32.2.1 Wave along +x

Ey = E0 sin(kx − ωt)
Bz = B0 sin(kx − ωt)
  1. E0, B0: amplitudes of the fields.
  2. Other forms: sin(ωt − kx), or sin ω(t − xc).
k = 2πλ  ·  ω = 2πf
c = fλ = ωk
READING IT

32.2.2 What the equation tells you

In the phaseMeaning
kx − ωttravels along +x
kx + ωttravels along −x
number with xk, and λ = 2πk
number with tω, and f = ω2π
number in frontamplitude
AMPLITUDES

32.2.3 E0 = cB0

E0B0 = EB = c
  1. True at every point and every instant, not only at the peaks.
  2. So BE = 1c.
  3. The frequency is not needed to find one field from the other.
E0 = √2 Erms  ·  B0 = √2 Brms
WRITING THE OTHER FIELD

32.2.4 B from E, or E from B

  1. Step 1: amplitude from E0 = cB0.
  2. Step 2: keep the same phase: same sin or cos, same bracket.
  3. Step 3: direction from E × B = direction of travel.
FORCE ON A CHARGE

32.2.5 Lorentz force

F = qE + q(v × B)
  1. Electric force: FE = qE.
  2. Magnetic force, v ⊥ B: FB = qvB.
  3. Since E = cB:
FEFB = cv
Practise PYQs on this topicNature of EM Waves & Wave Equation · 93 questions with solutions
03
CONCEPT

Displacement Current, Maxwell’s Equations & Production

In one line
Maxwell found that a changing electric field also makes a magnetic field. He called this term the displacement current.
AMPERE’S LAW

32.3.1 Where it fails

∮B · dl = μ0 i
  1. Holds only for steady current.
  2. Take a capacitor being charged by a battery.
+−+q−qil₁l₂
Loop l₁ is around the wire; loop l₂ is between the plates
  1. Loop l₁: ∮B · dl = μ0i.
  2. Loop l₂: no current passes, so the law gives 0.
  3. But a magnetic field is found between the plates. So the law fails.
DISPLACEMENT CURRENT

32.3.2 Ampere-Maxwell law

id = ε0 dφEdt
∮B · dl = μ0(ic + id)
  1. ic: conduction current, from flow of charges.
  2. id: from the changing electric field. It has the dimension of current.
  3. Between the plates, id = current in the connecting wires.
CAPACITOR RESULTS

32.3.3 Working forms

id = C dVdt = ε0Ad dVdt
AC: I0 = V0ωC  ·  Irms = VrmsωC
  1. E is uniform, so a part of area A0 carries id × A0A.
  2. Leaky capacitor: conduction and displacement currents cancel, so B = 0 between the plates.
CONDUCTING MEDIUM

32.3.4 Comparing the two currents

Jc = σE  ·  Jd = ε dEdt
Jc, maxJd, max = σωε
MAXWELL’S EQUATIONS

32.3.5 The four laws

LawEquation
Gauss (electrostatics)∮E · ds = qε0
Gauss (magnetism)∮B · ds = 0
Faraday (EMI)∮E · dl = −dφBdt
Ampere-Maxwell∮B · dl = μ0(ic + ε0dφEdt)
  1. For static fields ∮E · dl = 0; Faraday’s form is needed when B changes.
PRODUCTION

32.3.6 What makes an EM wave?

  1. Stationary charge: only an E field.
  2. Uniform velocity: steady E and B, no wave.
  3. Accelerated charge: radiates an EM wave.
  4. A charge oscillating harmonically gives a wave of the same frequency.
  5. An LC oscillator gives waves of a chosen frequency:
ν = 12π√(LC)
LC oscillatorlineEM wave
LC oscillator feeding an antenna
HISTORY

32.3.7 Who did what

NameWork
Maxwellfirst predicted EM waves
Hertzproduced and detected them, λ about 6 m
J. C. Boseproduced λ from 5 mm to 25 mm
Marconitransmitted them over a few km
JEE · NEET

Corner

Hertz’s experiment
Induction coilP₁P₂S₁S₂gapReceiver
Hertz’s set-up
  1. Plates P₁ and P₂ act as a capacitor.
  2. Wires joining spheres S₁, S₂ to the plates give a low inductance.
  3. High voltage makes a spark across the gap; the spark sets up oscillations.
  4. The oscillations send out EM waves, picked up by the receiver ring.
ν = 12π√(LC)
Practise PYQs on this topicDisplacement Current, Maxwell's Equations & Production · 15 questions with solutions
04
CONCEPT

Speed of EM Waves in a Medium

In one line
In vacuum every EM wave travels at c. In a medium it slows down by the factor n = √(μrεr).
VACUUM

32.4.1 Speed in free space

c = 1√μ0ε0 = E0B0 = 3 × 108 m/s
  1. Same in all directions.
  2. Does not depend on the motion of the source.
  3. Same for all wavelengths in vacuum.
MEDIUM

32.4.2 Speed in a medium

v = 1√(με) = c√μrεr
  1. μ = μrμ0, ε = εrε0.
  2. Dielectric constant k is the same as εr.
  3. Speed in a medium depends on wavelength (dispersion), not on intensity.
REFRACTIVE INDEX

32.4.3 Link with n

n = cv = √μrεr
  1. Non-magnetic medium, μr = 1:
n = √εr  ·  εr = n²
n = √μεμ0ε0
FROM THE EQUATION

32.4.4 Reading v from a wave

v = ωk = E0B0
  1. Find v from the two numbers in the phase.
  2. Then n = cv, and εr = n² (non-magnetic).
  3. Time for an echo: t = 2dv.
ENTERING A MEDIUM

32.4.5 What changes

QuantityIn the medium
frequencyunchanged
speedv = cn
wavelengthλm = λn
wave numberkm = nk
cv = sin isin r
JEE · NEET

Corner

Wave impedance
  1. Hindrance a medium offers to the wave.
  2. H is the magnetic intensity: H = Bμ.
Z = EH = √με = √μrεr √μ0ε0
free space: Z = √μ0ε0 = 376.6 Ω ≈ 120π Ω
Practise PYQs on this topicSpeed of EM Waves in a Medium · 28 questions with solutions
05
CONCEPT

Energy Density

In one line
The energy of an EM wave is shared equally by its electric and magnetic fields.
AT ANY INSTANT

32.5.1 Energy per unit volume

uE = 12ε0E²
uB = B²2μ0
  1. Using E = cB, these two are always equal.
  2. Same result in a medium, with ε and μ.
u = uE + uB = ε0E² = B²μ0
AVERAGE VALUES

32.5.2 Over one cycle

QuantityValue
average electric14ε0E0²
average magneticB0²4μ0
total average12ε0E0² = B0²2μ0
  1. The average of sin²ωt is one half.
  2. Ratio of average electric to average magnetic = 1.
  3. Ratio of average electric to total average = 12.
uav = ε0Erms²
ENERGY IN A VOLUME

32.5.3 Total energy

U = uav × V
  1. Same energy in a smaller volume needs a larger E0: E0² ∝ 1V.
  2. Half the diameter of a cylinder: V becomes one fourth, so E0 doubles.
HOW IT VARIES

32.5.4 Oscillation of energy

  1. u ∝ E² ∝ sin²ωt.
  2. So the energy in a small volume oscillates at twice the frequency of the wave.
Practise PYQs on this topicEnergy Density & Intensity · 36 questions with solutions
06
CONCEPT

Intensity

In one line
Intensity is the energy crossing unit area per unit time, on a surface perpendicular to the direction of travel.
DEFINITION

32.6.1 Energy flow

I = energyarea × time = uav × c
cAlength = c × Δt
All the energy in a column of length cΔt crosses area A in time Δt
  1. Unit: W/m². Also called energy flux.
  2. E and B contribute equally: ratio 1 : 1.
FROM AMPLITUDES

32.6.2 Working formula

I = 12ε0E0²c = cB0²2μ0
E0 = √2Iε0c  ·  B0 = E0c
  1. ε0c = 2.655 × 10−3 in SI: a handy number.
  2. √2Iε0c has the unit of electric field, N/C.
  3. In terms of rms: I = ε0Erms²c.
LASER BEAM

32.6.3 Power and area

I = PA
IN A MEDIUM

32.6.4 Refractive index n

I = 12nε0cE0²
  1. With a fraction reflected: Itransmitted = (1 − r)I.
POINT SOURCE

32.6.5 Bulb, lamp, LED

rarea = 4πr²
Power spreads over a sphere
I = Prad4πr²
  1. Prad = efficiency × rated power.
  2. I ∝ 1r², and E0 ∝ 1r.
  3. All points at the same r have the same I, whatever the angle.
  4. Intensity due to the electric field alone = I2.
JEE · NEET

Corner

Poynting vector
  1. Rate of energy flow per unit area; unit W/m².
  2. Points along the direction of travel.
S = 1μ0 (E × B)
Smax = E0B0μ0
Sav = E0B02μ0 = 12ε0E0²c = cB0²2μ0
  1. Its direction does not oscillate; its size swings between 0 and Smax.
  2. Sav is the intensity I.
Practise PYQs on this topicEnergy Density & Intensity · 36 questions with solutions
07
CONCEPT

Momentum & Radiation Pressure

In one line
EM waves have no rest mass, yet they carry momentum, so they push on any surface they strike.
MOMENTUM

32.7.1 Carried by the wave

p = Uc
absorbedreflected
Momentum given: absorbing Uc, reflecting 2Uc
SurfaceMomentum delivered
fully absorbingUc
fully reflecting2Uc
fraction r reflected(1 + r)Uc
FORCE

32.7.2 On a surface of area A

  1. Energy per second on the surface = IA.
  2. Force = momentum delivered per second.
SurfaceForce F
absorbingIAc
reflecting2IAc
fraction r reflected(1 + r)IAc
  1. The time of exposure does not change the force or the pressure.
  2. It only changes the total momentum: p = F × t.
RADIATION PRESSURE

32.7.3 Force per unit area

Pabsorbing = Ic
Preflecting = 2Ic
  1. Check the units: change W/cm² to W/m² when A is in m².
  2. I can be found first from the amplitude of E.
IN A MEDIUM

32.7.4 Wave speed v

Pabsorbing = Iv = nIc
JEE · NEET

Corner

Force on a reflecting hemisphere
  1. Point source of power P at the centre, inner surface fully reflecting.
  2. Sideways parts of the force cancel; only the axial part adds up over projected area πR².
F = 2Ic × πR² = P2c
Practise PYQs on this topicMomentum & Radiation Pressure · 14 questions with solutions
08
CONCEPT

Electromagnetic Spectrum: Order & Ranges

In one line
The whole ordered range of frequencies and wavelengths of EM waves is the EM spectrum.
ORDER

32.8.1 Shortest to longest wavelength

γXUVVisIRMicroRadio10⁻³ nm1 nm400 nm700 nm1 mm0.1 mwavelength increasesfrequency and photon energy increase
The EM spectrum
γ < X < UV < visible < IR < micro < radio
  1. Wavelength rises left to right; frequency and photon energy fall.
  2. All of them travel at the same speed c in vacuum.
RANGES

32.8.2 Wavelength of each part

WaveWavelength
Radioabove 0.1 m
Microwave0.1 m to 1 mm
Infrared1 mm to 700 nm
Visible700 nm to 400 nm
Ultraviolet400 nm to 1 nm
X-rays1 nm to 10−3 nm
Gamma raysbelow 10−3 nm
VISIBLE LIGHT

32.8.3 VIBGYOR

  1. Violet has the shortest wavelength (about 400 nm).
  2. Red has the longest wavelength (about 700 nm).
  3. Blue photon has more energy than yellow.
PHOTON ENERGY

32.8.4 Finding the region

E = hf = hcλ
λ(nm) ≈ 1240E(eV)
  1. A photon of about 10 keV gives λ near 0.1 nm: X-ray region.
NOT EM WAVES

32.8.5 Watch out

  1. α-rays and β-rays are charged particles.
  2. Cathode rays are electrons.
  3. Sound is a mechanical wave.
  4. Heat rays are infrared, so they are EM waves.
Practise PYQs on this topicElectromagnetic Spectrum & Atmosphere · 47 questions with solutions
09
CONCEPT

Production, Uses & the Atmosphere

In one line
Each part of the spectrum has its own source and its own uses. The atmosphere decides which of them reach us.
PRODUCTION

32.9.1 Source of each wave

WaveProduced by
Radiorapid acceleration of electrons in aerials
Microwaveklystron valve, magnetron
Infraredvibration of atoms and molecules
Visibleouter electrons changing levels
Ultravioletinner electrons, arc lamps
X-raysinner shell electrons, X-ray tube
Gamma raysradioactive decay of the nucleus
USES

32.9.2 What each wave does

WaveUses
RadioAM and FM, TV, communication
Microwaveradar, aircraft navigation, oven
Infraredphysiotherapy, muscular strain, night and fog photography, remote control
Visibleto see objects
Ultravioletsterilizing, water purification, food preservation, Lasik surgery, finger prints
X-raysmedical diagnosis, crystal structure
Gamma raysnuclear structure, cancer treatment
WORTH REMEMBERING

32.9.3 Common questions

  1. Microwave oven: its frequency matches the resonant frequency of water molecules.
  2. Human body radiates all the time, in the infrared.
  3. X-rays study crystals: their λ is close to the atomic spacing.
  4. To observe a particle, choose λ of the order of its size.
  5. Radio waves diffract more than microwaves: longer λ.
  6. Object much smaller than λ: the wave is scattered.
  7. Optical waves have shorter λ than microwaves.
GREENHOUSE EFFECT

32.9.4 Warming of the earth

EarthCO₂ and cloudssunlightinfrared
Infrared from the earth is sent back
  1. Infrared from the earth is reflected back by low clouds and CO₂.
  2. So the cause is infrared rays.
OZONE LAYER

32.9.5 The UV shield

  1. Absorbs most of the sun’s ultraviolet rays.
  2. Blocks wavelengths below about 3 × 10−7 m.
  3. This protects living cells.
RADIO PROPAGATION

32.9.6 How signals travel

EarthIonospheresky waveground wave
Ground wave and sky wave
  1. Ground wave: follows the surface of the earth.
  2. Sky wave: reflected back by the ionosphere.
  3. AM band: frequency up to 30 MHz. Amplitude of the carrier follows the signal.
  4. FM band: 80 MHz to 200 MHz. Frequency of the carrier follows the signal.
JEE · NEET

Corner

Layers of the atmosphere
Appleton layerKennelly-Heaviside layerThermosphereMesosphereOzone layerStratosphereTroposphereEarthIonosphere≈ 12 km≈ 50 km≈ 80 km≈ 480 km
Layers above the earth
  1. 78% N₂, 21% O₂, traces of other gases.
  2. Troposphere: temperature falls from 290 K to 220 K with height.
  3. Stratosphere: temperature 220 K to 200 K.
  4. Mesosphere: temperature falls to 180 K.
  5. Ionosphere: ions, electrons and neutral molecules.
  6. Kennelly-Heaviside layer: about 110 km up, very high electron density.
Radio bands
BandFrequency
VLF10 kHz to 30 kHz
LF30 kHz to 300 kHz
MF (MW)300 kHz to 3000 kHz
HF (SW)3 MHz to 30 MHz
VHF30 MHz to 300 MHz
UHF300 MHz to 3000 MHz
SHF (micro)3000 MHz to 300000 MHz
TV signals and antenna height
hRddOADC
Range of a tall antenna
  1. TV signals are frequency modulated.
  2. h = antenna height, R = radius of the earth.
d = √(2hR)
area covered A = πd² = 2πhR
  1. Population covered = area × population density.
Practise PYQs on this topicElectromagnetic Spectrum & Atmosphere · 47 questions with solutions
EXAM-DAY CARD

Just see this before the exam

EM Waves
E0B0 = c
wave
id = ε0dφEdt
displacement current
n = √μrεr
medium
I = 12ε0E0²c
intensity
P = Ic or 2Ic
radiation pressure
γ X UV V IR M R
spectrum
FORMULA SHEET

Whole chapter on one page

Wave

travel along E × B

Ey = E0 sin(kx − ωt)

k = 2πλ, c = ωk = fλ

E0 = cB0

Maxwell

id = ε0dφEdt = CdVdt

∮B·dl = μ0(ic + id)

Jc to Jd = σ to ωε

ν = 12π√(LC)

Medium

c = 1√μ0ε0

v = c√μrεr

n = cv = √μrεr

f same, λm = λn

Energy

uE = 12ε0E², uB = B²2μ0

uE = uB

uav = 12ε0E0²

U = uavV

Intensity

I = uavc = 12ε0E0²c

I = cB0²2μ0

point source: I = P4πr²

laser: I = PA

Pressure

absorbing: p = Uc, P = Ic

reflecting: p = 2Uc, P = 2Ic

F = (1 + r)IAc

λ(nm) ≈ 1240E(eV)

TOP MISTAKES

Avoid these = easy marks

MISTAKE ✗

Direction of travel from B × E

Using c in a medium

Total uav = ¼ε0E0²

Reflecting surface: F = IAc

CORRECT ✓

Always use E × B

v = cn, and frequency stays the same

¼ is electric alone; total is ½ε0E0²

Reflecting: F = 2IAc