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Laws of Motion PYQs · MHT CET · JEE Main · NEET

Equilibrium, Third Law & Frames

Questions
25
MHT CET
5
JEE Main
18
NEET
2
Years
2002–2026
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Q1MHT CET 2026 · 19 APR · SHIFT 1Easy

Equilibrium, Third Law & Frames · Frames of reference & pseudo force

Which of the following person is in an inertial frame of reference?

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Answer: (b)

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Q2JEE Main 2026 · 24 JAN · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A flexible chain of mass mm hangs between two fixed points at the same level. The inclination of the chain with the horizontal at the two points of support is 30∘30^\circ. Considering the equilibrium of each half of the chain, the tension of the chain at the lowest point is ______.

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Answer: (b)

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Q3JEE Main 2025 · 2 APR · SHIFT 2Easy

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

Figure

A body of mass 1 kg is suspended with the help of two strings making angles as shown in figure. Magnitudes of tensions T1T_1 and T2T_2, respectively, are (in N):

(Take acceleration due to gravity 10 m/s210\text{ m/s}^2)

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Answer: (a)

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Q4MHT CET 2025 · 20 APR · SHIFT 1Easy

Equilibrium, Third Law & Frames · Frames of reference & pseudo force

Which one of the following person is in an inertial frame of reference?

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Answer: (c)

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Q5MHT CET 2025 · 26 APR · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A mass ' M ' is suspended by a rope from a rigid support at point ' P ' as shown in figure. Another rope is tied at end ' Q ' and pulled horizontally with a force ' FF '. If the rope makes an angle ' θ\theta ' with vertical then the tension in the string ' PQ ' is

Figure

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Answer: (b)

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Q6JEE Main 2025 · 4 APR · SHIFT 1Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A body of mass mm is suspended by two strings making angles θ1\theta_1 and θ2\theta_2 with the horizontal ceiling with tensions T1T_1 and T2T_2 simultaneously. T1T_1 and T2T_2 are related by T1=3T2T_1 = \sqrt{3}T_2, the angles θ1\theta_1 and θ2\theta_2 are

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Answer: (d)

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Q7JEE Main 2024 · 6 APR · SHIFT 2Easy

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A body of weight 200 N200\text{ N} is suspended from a tree branch through a chain of mass 10 kg10\text{ kg}. The branch pulls the chain by a force equal to (if g=10 m/s2g = 10\text{ m/s}^2):

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Answer: (a)

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Q8MHT CET 2024 · 15 MAY · SHIFT 1Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

The pulleys and strings shown in figure are smooth and of negligible mass. For the system to remain in equilibrium, angle θ\theta should be

Figure

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Answer: (d)

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Q9JEE Main 2024 · 9 APR · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A 1 kg1\text{ kg} mass is suspended from the ceiling by a rope of length 4 m4\text{ m}. A horizontal force 'FF' is applied at the mid point of the rope so that the rope makes an angle of 45∘45^\circ with respect to the vertical axis as shown in figure. The magnitude of FF is:

(Assume that the system is in equilibrium and g=10 m/s2g = 10\text{ m/s}^2)

Figure

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Answer: (b)

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Q10JEE Main 2023 · 12 APR · SHIFT 1Easy

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Three forces F1=10 N, F2=8 N, F3=6 NF_1 = 10\text{ N},\ F_2 = 8\text{ N},\ F_3 = 6\text{ N} are acting on a particle of mass 5 kg5\text{ kg}. The forces F2F_2 and F3F_3 are applied perpendicularly so that particle remains at rest. If the force F1F_1 is removed, then the acceleration of the particle is:

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Answer: (c)

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Q11JEE Main 2023 · 30 JAN · SHIFT 2Easy

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A block of 3 kg\sqrt{3}\text{ kg} is attached to a string whose other end is attached to the wall. An unknown force FF is applied so that the string makes an angle of 30∘30^\circ with the wall. The tension TT is: (Given g=10 m s−2g = 10\text{ m s}^{-2})

Figure

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Answer: (d)

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Q12MHT CET 2022 · 11 AUG · SHIFT 2Easy

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

A door 1.2 m1.2\text{ m} wide requires a force of 1 N1\text{ N} to be applied perpendicular at the free end to open or close it. The perpendicular force required at a point 0.2 m0.2\text{ m} distant from the hinges for opening or closing the door is

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Answer: (d)

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Q13JEE Main 2022 · 25 JUL · SHIFT 2Medium

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

For a free body diagram shown in the figure, the four forces are applied in the 'x' and 'y' directions. What additional force must be applied and at what angle with positive x-axis so that the net acceleration of body is zero?

Figure

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Answer: (a)

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Q14JEE Main 2022 · 25 JUL · SHIFT 1Medium

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Four forces are acting at a point PP in equilibrium as shown in figure. The ratio of force F1F_1 to F2F_2 is 1:x1 : x where x=x = _____________.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 3

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Q15JEE Main 2022 · 27 JUN · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is θ\theta = tan−1{}^{-1} (x ×\times 10−-1). The value of x is ____________.

(Given, g = 10 m/s2)

Numerical answer type. Work it out, then open the answer.

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Answer: 3

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Q16JEE Main 2021 · 31 AUG · SHIFT 2Easy

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Statement: 1

If three forces F⃗1,F⃗2\vec{F}_1, \vec{F}_2 and F⃗3\vec{F}_3 are represented by three sides of a triangle and F⃗1+F⃗2=−F⃗3\vec{F}_1 + \vec{F}_2 = -\vec{F}_3, then these three forces are concurrent forces and satisfy the condition for equilibrium. Statement: 2

A triangle made up of three forces F⃗1,F⃗2\vec{F}_1, \vec{F}_2 and F⃗3\vec{F}_3 as its sides taken in the same order, satisfy the condition for translatory equilibrium.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Answer: (d)

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Q17JEE Main 2021 · 31 AUG · SHIFT 1Difficult

Equilibrium, Third Law & Frames · Frames of reference & pseudo force

A car is moving on a plane inclined at 30∘^\circ to the horizontal with an acceleration of 10 ms−2{}^{-2} parallel to the plane upward. A bob is suspended by a string from the roof of the car. The angle in degrees which the string makes with the vertical is ______________. (Take g = 10 ms−2{}^{-2})

Numerical answer type. Work it out, then open the answer.

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Answer: 30

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Q18JEE Main 2020 · 7 JAN · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid point of the rope such that the top half of the rope makes an angle of 45° with the vertical. Then F equal: (Take g = 10 ms–2 and the rope to be massless)

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Answer: (a)

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Q19JEE Main 2019 · 9 JAN · SHIFT 2Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviates at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms−2{}^{-2})

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Answer: (d)

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Q20NEET 2019Medium

Equilibrium, Third Law & Frames · Frames of reference & pseudo force

A truck is stationary and has a bob suspended by a light string, in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of aa. The pendulum will tilt

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Answer: (c)

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Q21JEE Main 2013 · 9 APR · SHIFT 1Medium

Equilibrium, Third Law & Frames · Strings & ropes in equilibrium

A uniform sphere of weight W and radius 5 cm is being held by a string as shown in the figure. The tension in the string will be:

Figure

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Answer: (d)

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Q22NEET 2008 · AIPMTMedium

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Figure

Three forces acting on a body are shown in the figure. To have the resultant force only along the y- direction, the magnitude of the minimum additional force needed is

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Answer: (c)

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Q23JEE Main 2003 · AIEEEEasy

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Three forces start acting simultaneously on a particle moving with velocity,v⃗\vec{v} These forces are represented in magnitude and direction by the three sides of a triangle ABCABC. The particle will now move with velocity

Figure

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Answer: (d)

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Q24JEE Main 2002 · AIEEEEasy

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

When forces F1, F2, F3F_1,\ F_2,\ F_3 are acting on a particle of mass mm such that F2F_2 and F3F_3 are mutually perpendicular, then the particle remains stationary. If the force F1F_1 is now removed then the acceleration of the particle is

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Answer: (a)

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Q25JEE Main 2002 · AIEEEMedium

Equilibrium, Third Law & Frames · Force triangle, Lami & resultant

Two forces are such that the sum of their magnitudes is 18 N18\text{ N} and their resultant is 12 N12\text{ N} which is perpendicular to the smaller force. Then the magnitudes of the forces are

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Answer: (b)

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