YDSE: Fringe Width & Fringe Positions

In two separate Young's double-slit experimental set-ups and two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slits separations and that of the wavelengths of light used are $2 : 1$ and $1 : 2$ respectively. The corresponding ratio of the distances between the slits and the respective screens ( $D_1/D_2$) is ______。

In Young's double slit experiment, the separation between the slits is decreased to $\left(\frac{1}{3}\right)^{th}$ of its original distance and the distance between the slits and the screen is doubled. The fringe width

In Young's double slit experiment, the fringe width is $2.4$ mm with light of wavelength $9000$ A.U. If the light of wavelength $5400$ A.U. is used, with no other change in the experimental set up. The change in fringe width is

If fringe width is $0.4$ mm, the distance between fifth bright and third dark band on the same side in interference pattern of Young's double slit experiment is (in mm)

In Young's double slit experiment, the fringe width is 0.4 mm. What is the distance between $4$th dark band and $6$th bright band on the same side of the interference pattern?

Two coherent sources $P$ and $Q$ produce interference at a point $A$ on the screen where there is a dark band which is formed between $4$th bright band and $5$th bright band. Wavelength of light used is $6000$ Å. The path difference between $PA$ and $QA$ is $x \times 10^{-4}$ cm. The value of $x$ is

In a certain region of the screen, number of fringes formed is observed to be 8 in Young's double slit experiment when light of wavelength $6600$ Å is used. If the light of wavelength $4400$ Å is used, the number of fringes observed in the same region of the screen will be

Given below are two statements:

Statement I: In a Young's double slit experiment, the angular separation of fringes will increase as the screen is moved away from the plane of the slits

Statement II: In a Young's double slit experiment, the angular separation of fringes will increase when monochromatic source is replaced by another monochromatic source of higher wavelength In the light of the above statements, choose the correct answer from the options given below:

In Young's double slit experiment, following figure shows that $Q$ is the position of second bright fringe on the right side of point $O.\ P$ is the eleventh bright fringe on the other side measured from point $Q$. If the wavelength of light used is $6000$ Å, then what will be the value of $S_1B$?

In double slit experiment, the angular width of the fringes is $0.20^\circ$ for sodium light ($\lambda = 5890$ \AA). To increase the angular width of the fringes by $10\%$, the necessary change in wavelength is

In Young's double slit experiment the wavelength of light used is $6000\ \text{Å}$, the screen is 40 cm from the slits and the fringe width is 0.012 cm, the distance between two slits is

In a Young's double slit experiment, the slits are separated by 0.2 mm. If the slits separation is increased to 0.4 mm, the percentage change of the fringe width is:

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): In Young's double slit experiment, the fringes produced by red light are closer as compared to those produced by blue light.

Reason (R): The fringe width is directly proportional to the wavelength of light.

In the light of the above statements, choose the correct answer from the options given below:

In Young's double slit experiment, when light of wavelength 600 nm is used, 18 fringes are observed on the screen. If the wavelength of light is changed to 400 nm, the number of fringes observed on the screen is

Graph shows the variation of fringe width ( X) versus distance of the screen from the plane of the slits (D) in Young's double slit experiment. (keeping other parameters same, $d =$ distance between the slits). The wavelength of light used can be calculated as

In Young's double slit experiment with monochromatic light of wavelength 600 nm, the distance between the slits is $10^{-3}\text{ m}$. For changing the fringe width by $3 \times 10^{-5}\text{ m}$

a. the screen is moved away from the slit by 5 cm.

b. the screen is moved 5 cm towards the slits.

c. the screen is moved 3 cm towards the slits.

d. the screen is moved away from the slits by 3 cm.

The ratio of the distance of $n$th bright band and $m$th dark band from the central bright band in an interference pattern is

In a Young's double slit experiment wavelength of light used is $6000\ \text{Å}$. The first order maxima and tenth order maxima fall at 14.50 mm and 16.75 mm from the particular reference point in the interference pattern respectively. If the wavelength is changed to $5500\ \text{\AA}$ then the position of zero order and tenth order maxima are respectively

[The other arrangements remaining same]

A double slit interference experiment performed with a light of wavelength 600 nm forms an interference fringe pattern on a screen with 10 th bright fringe having its centre at a distance of 10 mm from the central maximum. Distance of the centre of the same 10 th bright fringe from the central maximum when the source of light is replaced by another source of wavelength 660 nm would be ________ mm.

Two slits in Young's double slit experiment are $1.5\text{ mm}$ apart and the screen is placed at a distance of $1\text{ m}$ from the slits. If the wavelength of light used is $600 \times 10^{-9}\text{ m}$ then the fringe separation is

In a double slit experiment, the distance between slits is increased 10 times, whereas their distance from screen is halved, the fringe width

How is the interference pattern affected when violet light replaces sodium light?

In young's double slit experiment, the $n$th maximum of wavelength $\lambda_1$ is at a distance of $y_1$ from the central maximum. When the wavelength of the source is changed to $\lambda_2, \left(\frac{n}{3}\right)$th maximum is at a distance of $y_2$ from its central maximum. The ratio $\frac{y_1}{y_2}$ is

In Young's double slit experiment, carried out with light of wavelength $5000\ \text{Å}$, the distance between the slits is $0.3\text{ mm}$ and the screen is at $200\text{ cm}$ from the slits. The central maximum is at $x = 0\text{ cm}$. The value of $x$ for third maxima is __________ $\text{mm}$.

If the monochromatic source in Young's double slit experiment is replaced by white light, then

Sodium light $(\lambda = 6 \times 10^{-7}\text{ m})$ is used to produce interference pattern. The observed fringe width is 0.12 mm. The angle between the two wave trains is

In Young's double slit experiment, the slits are separated by 0.6 mm and screen is placed at a distance of 1.2 m from slit. It is observed that the tenth bright fringe is at a distance of 8.85 mm from the third dark fringe on the same side. The wavelength of light used is

The fringe width in an interference pattern is ' X '. The distance between the sixth dark fringe from one side of central bright band to the fourth bright fringe on other side is

In Young's double slit experiment, green light is incident on two slits. The interference pattern is observed on a screen. Which one of the following changes would cause the observed fringes to be more closely spaced?

In Young's double slit experiment the separation between the slits is doubled without changing other setting of the experiment to obtain same fringe width, the distance 'D' of the screen from slit should be made

The width of fringe is $2\text{ mm}$ on the screen in a double slits experiment for the light of wavelength of $400\text{ nm}$. The width of the fringe for the light of wavelength 600 $\text{nm}$ will be:

In Young's double slit experiment, $8$th maximum with wavelength '$\lambda_1$' is at a distance '$d_1$ ' from the central maximum and $6$th maximum with wavelength '$\lambda_2$' is at a distance '$d_2$'. Then $\frac{d_2}{d_1}$ is

In Young's double slit experiment, the fifth maximum with wavelength '$\lambda_1$ ' is at a distance '$y_1$' and the same maximum with wavelength '$\lambda_2$' is at a distance '$y_2$ ' measured from the central bright band. Then $\frac{y_1}{y_2}$ is equal to [D and $d$ are constant]

In Young's double slit experiment, the fringe width is $2\text{ mm}$. The separation between the $13$th bright fringe and the $4$th dark fringe from the centre of the screen on same side will be

In Young's double slits experiment, the position of 5$^{\text{th}}$ bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is:

The path difference between two identical light waves at a point $Q$ on the screen is $3\mu\text{m}$. If wavelength of the waves is $5000\ \text{Å}$, then at point $Q$ there is

For Young's double slit experiment, two statements are given below:

Statement I: If screen is moved away from the plane of slits, angular separation of the fringes remains constant.

Statement II: If the monochromatic source is replaced by another monochromatic source of larger wavelength, the angular separation of fringes decreases.

In the light of the above statements, choose the correct answer from the options given below:

Two sources of light $0.6\text{ mm}$ apart and screen is placed at a distance of $1.2\text{ m}$ from them. A light of wavelength $6000\ \text{\AA}$ used. Then the phase difference between the two light waves interfering on the screen at a point at a distance $3\text{ mm}$ from central bright band is

If the screen is moved away from the plane of the slits in a Young's double slit experiment, then the:

Using Young's double slit experiment, a monochromatic light of wavelength 5000 $\text{Å}$ produces fringes of fringe width 0.5 mm. If another monochromatic light of wavelength 6000 $\text{Å}$ is used and the separation between the slits is doubled, then the new fringe width will be:

In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is __________ nm.

In a Young's double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is

In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by 5 $\times$ 10$-$2 m towards the slits, the change in fringe width is 3 $\times$ 10$-$3 cm. If the distance between the slits is 1 mm, then the wavelength of the light will be ____________ nm.

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is ____________.

In Young's double slit experiment, if the source of light changes from orange to blue then:

If the source of light used in a Young's double slit experiment is changed from red to violet:

In Young's double slit experiment, the distance of $n$th dark band from the central bright band in terms of bandwidth '$\beta$' is

In Young's double slit experiment, the $10$th maximum of wavelength '$\lambda_1$' is at a distance of '$Y_1$ ' from the central maximum. When the wavelength of the source is changed to '$\lambda_2$ ', $5^{th}$ maximum is at a distance '$Y_2$ ' from the central maximum. The ratio $\frac{Y_1}{Y_2}$ is

In Young's double slit experiment, the '$n^{\text{th}}$' maximum of wavelength '$\lambda_1$ ' is at a distance '$y_1$' from the central maximum. When the wavelength of the source is changed to '$\lambda_2$', $\left(\frac{n}{2}\right)$th maximum is at a distance of '$y_2$' from its central maximum. The ratio $\frac{y_1}{y_2}$ is

In Young's double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of 5890 $\text{Å}$ is :-

The path difference between two interfering light waves meeting at a point on the screen is $\left(\frac{57}{2}\right)\lambda$. The bond obtained at that point is

Two coherent sources of wavelength '$\lambda$' produce steady interference pattern. The path difference corresponding to 10$^{th}$ order maximum will be

Two coherent sources 'P' and 'Q' produce interference at point 'A' on the screen, where there is a dark band which is formed between 4th and 5th bright band. Wavelength of light used is 6000 $\text{Å}$. The path difference PA and QA is

In Young's double slit experiment, with a source of light having wavelength $6300\ \text{Å}$, the first maxima will occur when the

In Young's experiment, fringes are obtained on a screen placed at a distance $75\text{ cm}$ from the slits. When the separation between two narrow slits is doubled, then the fringe width is decreased. In order to obtain the initial fringe width, the screen should be moved through.

In the Young's double slit experiment, the distance between the slits varies in time as d(t) = d0 + a0 sin$\omega$t; where d0, $\omega$ and a0 are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as:

In a Young's double slit experiment, the slits are separated by 0.3 mm and the screen is 1.5 m away from the plane of slits. Distance between fourth bright fringes on both sides of central bright is 2.4 cm. The frequency of light used is ______________ $\times$ 1014 Hz.

White light is passed through a double slit and interference is observed on a screen 1.5 m away. The separation between the slits is 0.3 mm. The first violet and red fringes are formed 2.0 mm and 3.5 mm away from the central white fringes. the difference in wavelengths of red and violet light is ................ nm.

In Young's double slit experiment green light is incident on the two slits. The interference pattern is observed on a screen. Which one of the following changes would cause the observed fringes to be more closely spaced?

In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:

In a Young’s double slit experiment, 16 fringes are observed in a certain segment of the screen when light of a wavelength 700 nm is used. If the wavelength of light is changed to 400 nm, the number of fringes observed in the same segment of the screen would be

In a Young's double slit experiment 15 fringes are observed on a small portion of the screen when light of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when another light source of wavelength $\lambda$ is used. Then the value of $\lambda$ is (in nm) __________.

In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to

Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source ($\lambda$ = 632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at a distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close is

In a Young's double slit experiment, the separation between the slits is 0.15 mm. in the experiment, a source of light of wavelengh 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is:

In a Young's double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference

In a Young’s double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle $\frac{1}{40}$ by using light of wavelength $\lambda$1. When the light of wavelength $\lambda$2 is used a bright fringe is seen at the same angle in the same set up. Given that $\lambda$1 and $\lambda$2 are in visible range (380 nm to 740 nm), their values are -

In Young’s double slit experiment the separation d between the slits is 2 mm, the wavelength $\lambda$ of the light used is 5896 $\text{\AA}$ and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20°. To increase the fringe angular width to 0.21° (with same $\lambda$ and D) the separation between the slits needs to be changed to

In Young’s double slit experiment, the distance between slits and the screen is 1.0 m and monochromatic light of 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d0 between the slits. If the angular resolution of the eye is $\left(\frac{1}{60}\right)^\circ$, the value of d0 is close to:

In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width

This question has Statement-1 and Statement-2. Of the four choices given after the Statements, choose the one that best describes the two Statements.

Statement-1: In Young's double slit experiment, the number of fringes observed in the field of view is small with longer wavelength of light and is large with shorter wavelength of light. Statement-2: In the double slit experiment the fringe width depends directly on the wavelength of light.

Two coherent point sources $S_1$ and $S_2$ are separated by a small distance $'d'$ as shown. The fringes obtained on the screen will be

A Young's double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is

If yellow light emitted by sodium lamp in Young's double slit experiment is replaced by monochromatic blue light of the same intensity

In Young's double slit experiment carried out with light of wavelength $(\lambda) = 5000$ Å, the distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at $x = 0$. The third maximum (taking the central maximum as zeroth maximum) will be at $x$ equal to

In Young's experiment, two coherent sources are placed 0.90 mm apart and fringe are observed one metre away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would be

The Young's double slit experiment is performed with blue and with green light of wavelengths 4360 Å and 5460 Å respectively. If $x$ is the distance of 4th maxima from the central one, then