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Alternating Current PYQs · MHT CET · JEE Main · NEET

Series LCR Circuit

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64
MHT CET
36
JEE Main
19
NEET
9
Years
2004–2026
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Q1MHT CET 2026 · 18 APR · SHIFT 2Easy

Series LCR Circuit · Voltages and the phasor sum

In an LCR series circuit, the potential difference across the terminals of the inductor, capacitor and resistor is 60 V, 30 V and 40 V respectively. Then supply voltage will be equal to

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Answer: (b)

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Q2MHT CET 2026 · 18 APR · SHIFT 2Easy

Series LCR Circuit · Impedance and current

In the series LCR circuit shown in figure the impedance is

Figure

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Answer: (b)

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Q3MHT CET 2026 · 16 APR · SHIFT 2Easy

Series LCR Circuit · Impedance and current

Series LCR circuit containing an a.c. source of 100V has a inductor and a capacitor of reactance 24 Ω24\ \Omega and 16 Ω16\ \Omega respectively. If a resistance of 6 Ω6\ \Omega is connected in series, then the potential difference across the series combination of inductor and capacitor only is

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Answer: (a)

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Q4MHT CET 2026 · 16 APR · SHIFT 1Easy

Series LCR Circuit · Impedance and current

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

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Answer: (a)

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Q5NEET 2026 · RE-NEETEasy

Series LCR Circuit · Impedance and current

An ac voltage V=220sin⁡(2×103t)V = 220 \sin\left(2 \times 10^{3} t\right) Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is:

(Given: L=10 mH, C=25 μF, R=100 ΩL = 10\text{ mH},\ C = 25\ \mu\text{F},\ R = 100\ \Omega)

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Answer: (b)

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Q6MHT CET 2026 · 12 MAY · SHIFT 2Medium

Series LCR Circuit · Impedance and current

In the given circuit, r.m.s. value of current through the resistor RR is

Figure

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Answer: (b)

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Q7MHT CET 2026 · 19 APR · SHIFT 1Medium

Series LCR Circuit · Impedance and current

For a series LCR circuit inductive reactance XLX_L is equal to resistance RR and also equal to twice the capacitive reactance XCX_C. The impedance of the circuit and the phase difference between voltage V and current i are respectively

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Answer: (c)

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Q8MHT CET 2026 · 11 APR · SHIFT 1Medium

Series LCR Circuit · Impedance and current

In the circuit shown below, the ac source has voltage V=30cos⁡(ωt)V = 30\cos(\omega t) volt with ω=2000\omega = 2000 rad/s. What will be the amplitude of the current?

Figure

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Answer: (c)

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Q9MHT CET 2026 · 13 MAY · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

In an LCR series circuit, a. c. voltage source is connected in series. When L is removed from the circuit, the phase difference between the voltage and the current is π/3\pi/3. If instead C is removed, the phase difference is again π/3\pi/3. The power factor of the circuit is (tan⁡π3=3)\left(\tan\frac{\pi}{3} = \sqrt{3}\right)

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Answer: (c)

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Q10MHT CET 2026 · 20 APR · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

In an LCR series circuit an alternating voltage source of frequency FF is connected. The current leads the voltage by 45∘45^\circ. The value of LL is

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Answer: (c)

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Q11MHT CET 2026 · 17 APR · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

The resistor 'RR' inductance 'LL' and capacitance 'CC' are connected in series with an a.c. source. When 'L' is removed from the circuit, the phase difference between voltage and current in the circuit is π3\frac{\pi}{3}. If instead, C is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is

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Answer: (d)

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Q12JEE Main 2026 · 2 APR · SHIFT 2Difficult

Series LCR Circuit · Phase angle: leading or lagging

The figure given below shows an LCR series circuit with two switches S1 and S2. When switch S1 is closed keeping S2 open, the phase difference (φ) between the current and source voltage is 30° and phase difference is 60° when S2 is closed keeping S1 open. The value of (3L1 − L2) is ______ H.

Figure

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Answer: (b)

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Q13MHT CET 2025 · 5 MAY · SHIFT 2Easy

Series LCR Circuit · Voltages and the phasor sum

The value of alternating e.m.f. (E) in the given circuit is

Figure

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Answer: (c)

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Q14MHT CET 2025 · 22 APR · SHIFT 2Easy

Series LCR Circuit · Impedance and current

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

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Answer: (b)

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Q15NEET 2025Easy

Series LCR Circuit · Impedance and current

To an ac power supply of 220 V at 50 Hz, a resistor of 20 Ω20\ \Omega, a capacitor of reactance 25 Ω25\ \Omega and an inductor of reactance 45 Ω45\ \Omega are connected in series. The corresponding current in the circuit and the phase angle between the current and the voltage is, respectively

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Answer: (d)

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Q16MHT CET 2025 · 26 APR · SHIFT 1Easy

Series LCR Circuit · Phase angle: leading or lagging

L,CL, C and R are connected in series to an a. c. source. Which one of the following is true? Phase relation between current and voltage is such that

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Answer: (d)

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Q17MHT CET 2025 · 21 APR · SHIFT 2Medium

Series LCR Circuit · Voltages and the phasor sum

An alternating e.m.f. having voltage V=V0sin⁡ωtV = V_0 \sin\omega t is applied to a series L-C-R circuit. Given: ∣XL−XC∣=R|X_L - X_C| = R. The r.m.s. value of potential difference across capacitor will be

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Answer: (c)

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Q18MHT CET 2025 · 19 APR · SHIFT 1Medium

Series LCR Circuit · Impedance and current

A series LCR circuit is connected to an a.c. source of 230 V, 50 Hz230\text{ V},\ 50\text{ Hz}. The circuit contains resistance of 80 Ω80\ \Omega an inductor having inductive reactance 70 Ω70\ \Omega and a capacitor of capacitive reactance 130 Ω130\ \Omega. The power factor of the circuit is xx. The value of xx is

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Answer: (b)

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Q19MHT CET 2025 · 5 MAY · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

An inductor of (100π) mH\left(\frac{100}{\pi}\right)\text{ mH}, capacitor of capacitance (10−32π) F\left(\frac{10^{-3}}{2\pi}\right)\text{ F} and resistance of 10 Ω10\ \Omega are connected in series with an AC voltage source of 110 V, 50 Hz110\text{ V},\ 50\text{ Hz} supply. The tangent of the phase angle ' ϕ\phi ' between voltage and current is

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Answer: (d)

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Q20MHT CET 2025 · 25 APR · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

In LCR series circuit, when ' LL ' is removed from the circuit, the phase difference between voltage and current in the circuit is π3\frac{\pi}{3}. If ' CC ' is removed from the circuit instead of LL then phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is (tan⁡60∘=3)\left(\tan 60^\circ = \sqrt{3}\right)

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Answer: (d)

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Q21MHT CET 2025 · 21 APR · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

In an electrical circuit ' RR ', ' LL ', ' CC ' and an a.c. voltage source are all connected in series. When ' L ' is removed from the circuit, the phase difference between the voltage and the current in the circuit is π3\frac{\pi}{3}. If instead ' CC ' is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is (tan⁡π3=3)\left(\tan\frac{\pi}{3} = \sqrt{3}\right)

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Answer: (d)

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Q22MHT CET 2024 · 16 MAY · SHIFT 2Easy

Series LCR Circuit · Voltages and the phasor sum

In an LCRLCR circuit, if ' VV ' is the effective value of the applied voltage, VRV_R is the voltage across ' RR ', ' VLV_L ' and ' VCV_C ' is the effective voltage across ' L ' and ' CC ' respectively then

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Answer: (c)

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Q23MHT CET 2024 · 9 MAY · SHIFT 2Easy

Series LCR Circuit · Impedance and current

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

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Answer: (c)

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Q24MHT CET 2024 · 9 MAY · SHIFT 1Easy

Series LCR Circuit · Impedance and current

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

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Answer: (b)

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Q25JEE Main 2024 · 5 APR · SHIFT 2Easy

Series LCR Circuit · Impedance and current

A series LCR circuit is subjected to an ac signal of 200 V, 50 Hz200\text{ V},\ 50\text{ Hz}. If the voltage across the inductor (L=10 mH)(L = 10\text{ mH}) is 31.4 V31.4\text{ V}, then the current in this circuit is _______.

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Answer: (a)

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Q26JEE Main 2024 · 5 APR · SHIFT 1Medium

Series LCR Circuit · Voltages and the phasor sum

An ac source is connected in given series LCR circuit. The rms potential difference across the capacitor of 20 μF20\ \mu\text{F} is __________ V.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 50

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Q27MHT CET 2024 · 10 MAY · SHIFT 2Medium

Series LCR Circuit · Impedance and current

For the series LCRLCR circuit, R=XL2=2XCR = \frac{X_L}{2} = 2X_C. The impedance of the circuit and the phase difference between V and I will be

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Answer: (b)

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Q28MHT CET 2024 · 11 MAY · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

An inductance of 300π mH\frac{300}{\pi}\text{ mH}, a capacitance of 1π mF\frac{1}{\pi}\text{ mF} and a resistance of 20 Ω20\ \Omega are connected in series with an a.c. source of 240 V, 50 Hz240\text{ V},\ 50\text{ Hz}. The phase angle of the circuit is

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Answer: (c)

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Q29MHT CET 2024 · 11 MAY · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

With an alternating voltage source frequency ' f ', inductor ' LL ', capacitor ' CC ' and resistance ' RR ' are connected in series. The voltage leads the current by 45∘45^\circ. The value of ' LL ' is (tan⁡45∘=1)(\tan 45^\circ = 1)

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Answer: (a)

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Q30MHT CET 2023 · 12 MAY · SHIFT 1Easy

Series LCR Circuit · Voltages and the phasor sum

In the given circuit, if dIdt=−1 A/s\frac{dI}{dt} = -1\text{ A/s} then the value of (VA−VB)(V_A - V_B) at this instance will be

Figure

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Answer: (a)

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Q31MHT CET 2023 · 11 MAY · SHIFT 2Easy

Series LCR Circuit · Voltages and the phasor sum

The a.c. source is connected to series LCR circuit. If voltage across RR is 40 V40\text{ V}, that across LL is 80 V80\text{ V} and that across CC is 40 V40\text{ V}, then the e.m.f. 'ee' of a.c. source is

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Answer: (b)

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Q32MHT CET 2023 · 11 MAY · SHIFT 1Easy

Series LCR Circuit · Voltages and the phasor sum

In series LCR circuit, the voltage across the inductance and the capacitance are not

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Answer: (d)

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Q33NEET 2023Easy

Series LCR Circuit · Voltages and the phasor sum

An ac source is connected in the given circuit. The value of ϕ\phi will be:

Figure

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Answer: (d)

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Q34MHT CET 2023 · 14 MAY · SHIFT 1Easy

Series LCR Circuit · Impedance and current

The reciprocal of the total effective resistance of LCR a.c. circuit is called

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Answer: (b)

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Q35NEET 2023Easy

Series LCR Circuit · Impedance and current

If Z1{}_{1} and Z2{}_{2} are the impedances of the given circuits (a) and (b) as shown in figures, then choose the correct option

Figure

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Answer: (a)

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Q36NEET 2023Easy

Series LCR Circuit · Impedance and current

The net impedance of circuit (as shown in figure) will be:

Figure

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Answer: (b)

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Q37JEE Main 2023 · 31 JAN · SHIFT 1Easy

Series LCR Circuit · Impedance and current

If R,XLR, X_L, and XCX_C represent resistance, inductive reactance and capacitive reactance. Then which of the following is dimensionless:

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Answer: (c)

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Q38MHT CET 2023 · 12 MAY · SHIFT 1Medium

Series LCR Circuit · Impedance and current

In the given circuit, r.m.s. value of current through the resistor RR is

Figure

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Answer: (a)

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Q39JEE Main 2023 · 30 JAN · SHIFT 2Medium

Series LCR Circuit · Impedance and current

In the given circuit, rms value of current (Irms)(I_{\text{rms}}) through the resistor RR is:

Figure

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Answer: (b)

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Q40MHT CET 2023 · 14 MAY · SHIFT 1Medium

Series LCR Circuit · Phase angle: leading or lagging

An alternating voltage is applied to a series LCR circuit. If the current leads the voltage by 45∘45^\circ, then (tan⁡45∘=1)(\tan 45^\circ = 1)

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Answer: (a)

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Q41MHT CET 2023 · 10 MAY · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

With an alternating voltage source of frequency 'ff', inductor 'LL', capacitor 'CC' and resistance 'RR' are connected in series. The voltage leads the current by 45∘45^\circ. The value of 'LL' is (tan⁡45∘=1)(\tan 45^\circ = 1)

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Answer: (a)

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Q42JEE Main 2022 · 27 JUN · SHIFT 2Easy

Series LCR Circuit · Impedance and current

If L, C and R are the self inductance, capacitance and resistance respectively, which of the following does not have the dimension of time?

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Answer: (d)

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Q43JEE Main 2022 · 30 JUL · SHIFT 2Medium

Series LCR Circuit · Impedance and current

A sinusoidal voltage V(t)=200sin⁡2000tV(t) = 200\sin 2000t volt is applied to a series LCR circuit in which L=10 mH, C=25 μFL = 10\text{ mH},\ C = 25\ \mu\text{F} and R=100 ΩR = 100\ \Omega. The impedance of the circuit is _______ Ω\Omega

Numerical answer type. Work it out, then open the answer.

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Answer: 100

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Q44JEE Main 2022 · 25 JUN · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

A sinusoidal voltage V(t) = 210 sin 3000 t volt is applied to a series LCR circuit in which L = 10 mH, C = 25 μ\muF and R = 100 Ω\Omega. The phase difference (Φ\Phi) between the applied voltage and resultant current will be:

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Answer: (a)

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Q45JEE Main 2022 · 28 JUN · SHIFT 2Difficult

Series LCR Circuit · Voltages and the phasor sum

In the given circuit, the magnitude of VL and VC are twice that of VR. Given that f = 50 Hz, the inductance of the coil is 1Kπ\frac{1}{K\pi} mH. The value of K is ____________.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 0

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Q46JEE Main 2022 · 29 JUL · SHIFT 2Difficult

Series LCR Circuit · Impedance and current

A circuit element XX when connected to an a.c. supply of peak voltage 100 V100\text{ V} gives a peak current of 5 A5\text{ A} which is in phase with the voltage. A second element YY when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by π2\frac{\pi}{2}. If XX and YY are connected in series to the same supply, what will be the rms value of the current in ampere?

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Answer: (d)

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Q47MHT CET 2021 · 23 SEP · SHIFT 1Easy

Series LCR Circuit · Voltages and the phasor sum

For series LCR circuit, which one of the following is a CORRECT statement?

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Answer: (a)

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Q48MHT CET 2021 · 23 SEP · SHIFT 1Easy

Series LCR Circuit · Voltages and the phasor sum

In an LCR series a.c. circuit, the voltage across each of the components L, C and R is 60 V. The voltage across the LC combination is

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Answer: (c)

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Q49JEE Main 2021 · 31 AUG · SHIFT 1Easy

Series LCR Circuit · Impedance and current

In an ac circuit, an inductor, a capacitor and a resistor are connected in series with XL = R = XC. Impedance of this circuit is:

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Answer: (c)

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Q50JEE Main 2021 · 25 FEB · SHIFT 1Medium

Series LCR Circuit · Voltages and the phasor sum

The angular frequency of alternating current in a L-C-R circuit is 100 rad/s. The components connected are shown in the figure. Find the value of inductance of the coil and capacity of condenser.

Figure

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Answer: (b)

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Q51MHT CET 2021 · 24 SEP · SHIFT 1Medium

Series LCR Circuit · Impedance and current

In the circuit shown in the figure, a.c. source gives voltage V=20cos⁡(2000t)V = 20\cos(2000t). Impedance and r.m.s. current respectively will be

Figure

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Answer: (c)

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Q52MHT CET 2021 · 20 SEP · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

A series LCR circuit with resistance (R) 500 ohm500\text{ ohm} is connected to an a.c. source of 250 V250\text{ V}. When only the capacitance is removed, the current lags behind the voltage by 60∘60^\circ. When only the inductance is removed, the current leads the voltage by 60∘60^\circ. The impedance of the circuit is (tan⁡π3=3)\left(\tan\frac{\pi}{3} = \sqrt{3}\right)

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Answer: (d)

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Q53JEE Main 2021 · 20 JUL · SHIFT 2Medium

Series LCR Circuit · Phase angle: leading or lagging

For a series LCR circuit with R = 100 Ω\Omega, L = 0.5 mH and C = 0.1 pF connected across 220V-\text{-}50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

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Answer: (d)

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Q54JEE Main 2020 · 9 JAN · SHIFT 2Medium

Series LCR Circuit · Impedance and current

In LC circuit the inductance L = 40 mH and

capacitance C = 100 μ\muF. If a voltage

V(t) = 10sin(314t) is applied to the circuit, the

current in the circuit is given as:

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Answer: (a)

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Q55NEET 2020 · PHASE 1Medium

Series LCR Circuit · Phase angle: leading or lagging

A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π3\frac{\pi}{3}. If instead C is removed from the circuit, the phase difference is again π3\frac{\pi}{3} between current and voltage. The power factor of the circuit is:

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Answer: (b)

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Q56MHT CET 2019 · 2 MAY · SHIFT 1Easy

Series LCR Circuit · Impedance and current

In a series LCRLCR circuit R=300 Ω, L=0.9 H, C=2 μF, ω=1000 rad/sR = 300\ \Omega,\ L = 0.9\text{ H},\ C = 2\ \mu\text{F},\ \omega = 1000\text{ rad/s}. The impedance of the circuit is

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Answer: (a)

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Q57JEE Main 2017 · 9 APR · SHIFT 1Difficult

Series LCR Circuit · Impedance and current

A sinusoidal voltage of peak value 283 V and angular frequency 320/s is applied to a series LCR circuit. Given that R=5 Ω\Omega, L=25 mH and C=1000 μ\muF. The total impedance, and phase difference between the voltage across the source and the current will respectively be:

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Answer: (b)

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Q58JEE Main 2014 · 9 APR · SHIFT 1Medium

Series LCR Circuit · Voltages and the phasor sum

When the rms voltages VL, VC and VR are measured respectively across the inductor L, the capacitor C and the resistor R in a series LCR circuit connected to an AC source, it is found that the ratio VL: VC: VR = 1: 2: 3. If the rms voltage of the AC source is 100 V, then VR is close to:

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Answer: (c)

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Q59JEE Main 2013 · 9 APR · SHIFT 1Medium

Series LCR Circuit · Voltages and the phasor sum

In the circuit shown here, the voltage across L and C are respectively 300 V and 400 V. The voltage E of the ac source is:

Figure

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Answer: (c)

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Q60NEET 2012 · AIPMT · PRELIMSMedium

Series LCR Circuit · Phase angle: leading or lagging

In an electrical circuit R, L, C and a.c. voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and the current in the circuit is π3\frac{\pi}{3}. If instead, C is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is

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Answer: (c)

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Q61NEET 2010 · AIPMT · PRELIMSMedium

Series LCR Circuit · Voltages and the phasor sum

In the given circuit the reading of voltmeter V1 and V2 are 300 volts each. The reading of the voltmeter V3 and ammeter A are respectively

Figure

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Answer: (b)

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Q62NEET 2005 · AIPMTMedium

Series LCR Circuit · Phase angle: leading or lagging

In a circuit L, C and R are connected in series with an alternating voltage source of frquency ff The current leads the voltage by 45°. The value of C is

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Answer: (d)

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Q63JEE Main 2005 · AIEEEMedium

Series LCR Circuit · Phase angle: leading or lagging

The phase difference between the alternating current and emfemf is π2.\frac{\pi}{2}. Which of the following cannot be the constituent of the circuit?

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Answer: (a)

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Q64JEE Main 2004 · AIEEEEasy

Series LCR Circuit · Voltages and the phasor sum

In an LCRLCR series a.c.\text{a.c.} circuit, the voltage across each of the components, L,CL, C and RR is 50 V50\text{ V}. The voltage across the L-CL\text{-}C combination will be:

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Answer: (d)

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